HELP! If A = (1, 1) B = (3, 3) and C = (5, 1), classify the the following triangle as either equilateral or isosceles. Type the word equilateral or isosceles in the blank. Answer for Blank 1:
http://www.wolframalpha.com/input/?i=triangle+%28+%281%2C+1%29+%2C+%283%2C+3%29+%2C+%285%2C+1%29%29
isosceles right triangle
Answer is isosceles, As from distance formula you have \[AB=\sqrt{(3-1)^2+(3-1)^2}=\sqrt{8}\] similarly you can have BC and AC (from which you'll get AC=sqrt(16) and BC = sqrt(8)) As, AB=AC but not equal to BC. Hence triangle is isosceles
Thanks to you both can you he lp with another one?
The following set of coordinates represents which figure? (3, -5), (5, -2), (10, -4), (8, -7) Parallelogram Rectangle Rhombus Square
The next question is this Quadrilateral ABCD has coordinates A (3, -5), B (5, -2), C (10, -4), D (8, -7). Quadrilateral ABCD is a rectangle, because opposite sides are congruent and adjacent sides are perpendicular square, because all four sides are congruent and adjacent sides are perpendicular parallelogram, because opposite sides are congruent and adjacent sides are not perpendicular rhombus, because all four sides are congruent and adjacent sides are not perpendicular
Use the same distance equation that I'd used above (of course if you don't want to plot those points on a graph, either you can do that in that way also). The equation is, \[d=\sqrt{(x_1-x_2)^2+(y_1-y_2)}\] put the respective values and check the distance AB, BC, CD and DA. Wait it's not over... Now what is all the sides are equal (which can result in square OR rhombous) or opposite two sides equal (which can result either in parallelogram or rectangle). For this just compare the diagonals (i.e AC and BD). If they are equal the they will result in square for first case and rectangle for second case
So confused
I'll recommend you to go with graph first. http://www.wolframalpha.com/input/?i=quadrilateral%28+%283%2C+-5%29+%2C+%285%2C+-2%29+%2C+%2810%2C+-4%29+%2C+%288%2C-7%29%29
Oh wow I'm stupid now it makes sense
Try this video on Distance Formula: https://www.khanacademy.org/math/algebra/linear-equations-and-inequalitie/more-analytic-geometry/v/distance-formula And after that try some problems here: http://www.regentsprep.org/Regents/math/geometry/GCG3/PracDistance.htm Doing self assessment will surely help. And never accept the direct answers. Always try to make your own approach.
Thanks
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