Ask your own question, for FREE!
Mathematics 28 Online
OpenStudy (anonymous):

Integration again

ganeshie8 (ganeshie8):

are they two different problems ?

OpenStudy (anonymous):

yes

OpenStudy (thomas5267):

\[ 3^{2y}=9^{y}=e^{y\ln{9}} \]

ganeshie8 (ganeshie8):

Or you may use the direct formula : \[\large \int a^x dx = \dfrac{a^x}{\ln a}\]

ganeshie8 (ganeshie8):

+C ofcourse

OpenStudy (anonymous):

Ohh. Okay. wait. haha

OpenStudy (anonymous):

i got 3^2y / ln9 +c. haha

OpenStudy (anonymous):

how about the second? =)

ganeshie8 (ganeshie8):

think of a clever substitution

ganeshie8 (ganeshie8):

\(\large x^{-2}\) and \(\large \dfrac{1}{x}\) should remind u somehting...

ganeshie8 (ganeshie8):

whats the derivative of 1/x ?

OpenStudy (thomas5267):

!!!!!!!!!!!! I thought we need to use integration by parts!

OpenStudy (anonymous):

its 1/x^2

ganeshie8 (ganeshie8):

which is same as \(\large x^{-2}\)

OpenStudy (anonymous):

yes yes/ =)

ganeshie8 (ganeshie8):

so whats ur substitution ? :)

ganeshie8 (ganeshie8):

btw, small mistake earlier : derivative of 1/x is -1/x^2 NOT 1/x^2

OpenStudy (anonymous):

missed the sign..

OpenStudy (anonymous):

ah! so its -e ^ 1/x +c =)))

ganeshie8 (ganeshie8):

looks good ^^

OpenStudy (thomas5267):

Mathematica returns the same answer. You are good to go.

OpenStudy (anonymous):

Thank you!!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!