Question

i have 3 questions please

1)
Select the equation of the line that passes through the point (-2, 3) and is perpendicular to the line on the graph.

y = 0

y = -2

y = 3

y = 3x


2)
Select the equation of a line that is perpendicular to the line on the graph and passes through the point (3, 2).

y = 1 over 3 x + 3

y = -1 over 3x + 3

y = 3 x + 2

y = - 1 over 3 x + 2

3)
Write the equation of the line that is parallel to the line y = -3x + 12 and passes through the point (-1, 6).

y = one thirdx + 7

y = -3x + 3

y = one thirdx + 3

y = -3x + 7

Answer 1

without the graph it's impossible to answer question 1. You'll know the slope from the graph

Answer 2

oh ya one sec

Answer 3

Ok, check on the graph for 2 neat points

one such neat point is (0,2) where the graph crosses the y-axis. Let's call that point 1 with (x1,y1)
another neat point on the graph is (1,5). Let's call that point 2 with (x2,y2)

with those two points you can calculate the slope

\[slope= \frac{ y _{2}-y _{1} }{ x _{2} -x _{1}}\]

you know that y2= 5 and y1=2, x2= 1 and x1=0

Let's plug in those numbers in the equasion

\[slope = \frac{ 5-2 }{ 1-0 }\]

first calculate the numenator, then calculate the denumenator, and divide the two

slope = ?

Now I'll explain something about linear equations (where the graph is straight line)

When the equation is "y=some number" but does not mention x then it is constant graph of a horizontal line. The slope = 0 then.
When the equation is "y= some number . x" it's a linear graph that either goes up or down (always look from left to right)

There is only one equation mentioned with an x, and we know the graph must have a slope. So, it's the last option that is the answer. And we can check whether the graph y=3x has the same slope as the one we calculated, because the "some number" that you multiply with x = slope.

Answer 4

still don't get this