The sum of two consecutive integers is 59. Write an equation that models this situation and find the values of the two integers.
If we call the first integer x, then what do we have to do to x to get to the next number right after it?
so you have two integers. Let's call them a and b. \[a+b=59\] but you also know that b is the next number between 0 and 59 after a \[b=a+1\] now use the second equasion by substituting the value of b in the first equasion a+a+1 = 59 simplify and calculate a = ? Once you know a, you know b because a+1 = b = ?
you see the one of the problems i'm not sure
I just used x for the first integer, and then x + 1 for the next. The sum of these two is represented as: x + (x + 1) = 59. x + x + 1 = 59... 2x + 1 = 59. Can you do that math?
consecutive integers means two integers where the second is one higher than the first x + (x+1) or a+b where b=a+1
yes I can and i've been but to it but its like non of these answers add up to it these ones I have to chose from
What do you have as a calculated result, and what are the options?
I have 4 to chose from 1: n+n+1=59;n20;+1=31 2: n+n2=59;n19;2n=38 3: n+n+1=59;n=29;n+1=28 4: n+n+1=59;n=29;n+1=30
n+n+1 is the correct expression, so 2 is wrong already if you work out n+n+1=59 -> 2n+1 = 59 -> 2n = 59- 1 -> 2n=58 -> n= 29 so n+1= 30 the last option is the correct one.
so the answer would be 4
like the 4th one
yes
thank you so much!!
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