How many negative roots will this function have? f(x) = x7 – 2x4 + 7x2 + 2x – 2
x = -1 is a solution, as -1 -2 + 7 -2 -2 = 0.
It's also evident that f'(x) is positive at x = -1, as f'(x) = 7x^6 - 8x^3 + 14x + 2 and f'(-1) = 7 + 8 - 14 + 2 = 3...note that this is POSITIVE. Yet f(0) = -2, so there must be a root somewhere in BETWEEN x = -1 and x = 0. The function has to get back down across the x axis.
As to negative roots of magnitude greater than -1, it's not possible, because the derivative will always be positive for x < -1. The 7x^6 and -8x^3 terms (both positive) in the derivative will always overwhelm the 14x term (only negative term) when x < -1.
So the answer is, two roots. One is -1, the other is between 0 and -1.
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