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OpenStudy (anonymous):
C3H8 + 5O2 → 3CO2 + 4H2O How many grams of O2 are required to react with 22 grams of propane?
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OpenStudy (anonymous):
80g of O2,,, C3H3 mol= C3H3 grams/ C3H3 molar mass =0.5mol O2 mol = C3H3 mol * 5 (full react) = 2.5mol {Mol*molar mass = mass} 2.5*32= 80g
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