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Chemistry 17 Online
OpenStudy (lovelyharmonics):

Which of the following is a possible set of quantum numbers for an electron? (1, 1, 0, +½) (2, 1, 1, +½) (3, 2, 3, -½) (3, -1, 0, -½)

OpenStudy (lovelyharmonics):

@ganeshie8 @Hero

OpenStudy (lovelyharmonics):

any ideas .-. i dont even understand this

ganeshie8 (ganeshie8):

(n, l, m, s)

ganeshie8 (ganeshie8):

n is a natural number l is a whole number and l = 0, 1, 2 ... (n-1)

ganeshie8 (ganeshie8):

so you can eliminate first and last options cuz : 1) first option n=l which is impossible 2) last option has l = negative number, which is also impossible

OpenStudy (lovelyharmonics):

where are we getting the numbers from .-.

ganeshie8 (ganeshie8):

please don't ask tough questions lol im very bad in chem :o

ganeshie8 (ganeshie8):

the magnetic quantum number m ranges from -l to l, so you can eliminate one other option, can you guess ?

OpenStudy (lovelyharmonics):

so we eliminate d.... then what?

ganeshie8 (ganeshie8):

we have eliminated A and D earlier

ganeshie8 (ganeshie8):

we don't need to eliminate it again.

ganeshie8 (ganeshie8):

the reason for eliminating A and D options is \(l\) - the angular momentum quantum number, it has to be less than \(n\)

ganeshie8 (ganeshie8):

options A and D fail that requirement, if that makes any sense...

OpenStudy (lovelyharmonics):

but c has two of the same numbers so that one cant be it right? so its b :D

OpenStudy (lovelyharmonics):

@ganeshie8

ganeshie8 (ganeshie8):

b is correct ! but c doesn't work for a different reason

ganeshie8 (ganeshie8):

the magnetic quantum number \(m\) ranges from \(-l\) to \(l\), but in option C, the value of \(m\) is greater than \(l\) so option C is impossible

OpenStudy (lovelyharmonics):

do you wana get alot more chem medals? :D

ganeshie8 (ganeshie8):

lol you're forcing me to learn chem! :D

OpenStudy (lovelyharmonics):

yussss but at least im not into the hard stuff yet XD

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