Which of the following is a possible set of quantum numbers for an electron? (1, 1, 0, +½) (2, 1, 1, +½) (3, 2, 3, -½) (3, -1, 0, -½)
@ganeshie8 @Hero
any ideas .-. i dont even understand this
(n, l, m, s)
n is a natural number l is a whole number and l = 0, 1, 2 ... (n-1)
so you can eliminate first and last options cuz : 1) first option n=l which is impossible 2) last option has l = negative number, which is also impossible
where are we getting the numbers from .-.
please don't ask tough questions lol im very bad in chem :o
the magnetic quantum number m ranges from -l to l, so you can eliminate one other option, can you guess ?
so we eliminate d.... then what?
we have eliminated A and D earlier
we don't need to eliminate it again.
the reason for eliminating A and D options is \(l\) - the angular momentum quantum number, it has to be less than \(n\)
options A and D fail that requirement, if that makes any sense...
but c has two of the same numbers so that one cant be it right? so its b :D
@ganeshie8
b is correct ! but c doesn't work for a different reason
the magnetic quantum number \(m\) ranges from \(-l\) to \(l\), but in option C, the value of \(m\) is greater than \(l\) so option C is impossible
this site has nice explanation : http://chemwiki.ucdavis.edu/Physical_Chemistry/Quantum_Mechanics/Quantum_Theory/Trapped_Particles/Atoms/Quantum_Numbers
do you wana get alot more chem medals? :D
lol you're forcing me to learn chem! :D
yussss but at least im not into the hard stuff yet XD
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