Question

got a couple questions
Write the equation of the line that is parallel to the line 3x - y = -3 and passes through the point (4, -2).

y = -one thirdx - 6

y = -one thirdx - 14

y = 3x - 6

y = 3x - 14

then
Write the equation of the line that is perpendicular to the line y = three halvesx + 4 and passes through the point (-6, 3).

y = three halvesx - 1

y = three halvesx + 3

y = -two thirdsx - 1

y = -two thirdsx + 3

Write the equation of the line that is parallel to the line y = -3x + 12 and passes through the point (-1, 6).

y = one thirdx + 7

y = -3x

Answer 1

answer for last question
y = one thirdx + 7

y = -3x + 3

y = one thirdx + 3

y = -3x + 7

Answer 2

Write the equation of the line that is parallel to the line 3x - y = -3 and passes through the point (4, -2).
Same method as we did last time. If you learn it you can answer all these on your own.

3x - y = -3
Put this in the form y = mx + b
Add y to both sides:
3x = y - 3
add 3 to both sides:
3x + 3 = y
or y = 3x + 3
compare this to y = mx + b where m is the slope.
m = 3.

Parallel lines have the same slope. So the slope of the line we are looking for is 3.
y = 3x + b
It passes through the point (4,-2)
put x = 4 and y = -2 and solve for b
-2 = 3(4) + b
-2 = 12 + b
b = -14

y = 3x - 14

Answer 3

ok can u stay just to see if i do the next one right

Answer 4

i got d bc

i add both sides like u said got 4.5 then so i got the x then for b i got 3

Answer 5

did i do it right