Question

A glass jar with a volume of 215cm^3 is designed to withstand a pressure of 253 KPa. The jar is filled with gas at a pressure of 152 KPa at ambient temperature. Can the glassware withstand the gas being heated to 2X10^2 Degree Celsius?

Answer 1

Pv=nRT
the variables i think i'll be working with are P/T=nR/V
P1/T1=P2/V2, where V1 is 152/25=253/T

Answer 2

i suppose its
better to use
P1/T1 = P2/T2

Answer 3

thats what i'm using but for some reason i'm not getting the right answer

Answer 4

sorry if i mistyped the furmula but that;s exactly what i'm using to find the temperature

Answer 5

alright did u do it like this?

253 000/ X = 152 000/ ((2X10^2) + 273)

Answer 6

i get, T2= 253X25/152=41.61C

Answer 7

look what i did

Answer 8

sorry for the late reply, i think the OS went down right after replied to my comment. Anyways why did you multiply the pressure by 1000????

Answer 9

coz its in Kpa
i need in Pa

Answer 10

SI system units

Answer 11

if i calculate the way you stated above, i get 787.30 which is not right

Answer 12

787.30- 273 =

Answer 13

514.3, which is still not right :(

Answer 14

what is the right answer?

Answer 15

the answer is 810 or 8.1X10^2

Answer 16

8.1X10^2

Answer 17

thats so weird

Answer 18

yep!!!! wait let me try myself

Answer 19

i extremely apologize the right answer is 241KPa and not 810...... i've double checked this time....

Answer 20

@Somy

Answer 21

oh

Answer 22

this is how i tried to do the questioin,

152X(101.3+273)/253 and i get 224.8KPa

Answer 23

101.3 ? where did u get this from?

Answer 24

it says that the experiment was done in 1 atm pressure which is 101.3

Answer 25

or ambient temperature

Answer 26

25C

Answer 27

oh i see btw if u r saying that 101.3 is pressure
then u r doing the calculation wrong

Answer 28

yah i jus realized LOL

Answer 29

i have no iead what i'm suppose to do....

Answer 30

lol 273 + Celsius degree = Kelvin
its unit conversion

Answer 31

u are adding 273 to pressure
which is obviously wrong

Answer 32

so what do i do then?????

Answer 33

first tell me what formula u used just now?
im confused

Answer 34

P1/T1 = P2/T2, where P1 is the initial pressure 152KPa/initial 25C= 253KPa/T2

Answer 35

but then you will find temperature tho

Answer 36

, the question asks whether or not the temperature i get is higher or lower than 200C which is what the glassware is designed for. so i get get i number less than 200, that means that the glassware can withstand the heat if not the temperature will be higher than 200C

Answer 37

im getting 223 Celsius

Answer 38

i'm getting 224

Answer 39

you are confusing me
u said
i extremely apologize the right answer is 241KPa and not 810...... i've double checked this time....

kpa is PRESSURE

Answer 40

so we need pressure

Answer 41

yah i jus realized that too.... so what am i suppose to do :'(

Answer 42

set the equation so that i'm solvign for pressure????

Answer 43

ok let me think properly coz i got too confused ~_~ with what u r saying and what the question is saying

Answer 44

got it

Answer 45

right

Answer 46

limit of the pressure of the jar = 253 KPa @ ambiant/25C
intial pressure of the jar= 152 KPa
what would be the pressure of the jar if the temperature is 200C

Answer 47

look
we will use P1/T1 = P2/T2
P1= 152 Kpa
T1= 25 Celsius +273= 298 K
P2= X
T2= 200 + 273= 473 K

Answer 48

so
152/298 = X/ 473
X= 473 *152/ 298 = 241kPa

Answer 49

right now i get the question ~_~ u mixed up the whole conversion stuff so i got confused

Answer 50

look when we use Gas law formulas we have to use temperature in Kelvin
always remember that
you used Celsius thats why you were getting stuff wrong + well you got the question wrong a bit too but well you were on the right way

so basically saying the question asked if it will with stand - if the temperature is increased
now that means we need to find pressure to which this temperature will lead us to, and then compare

Answer 51

i really appreciate the effort you put into solving the question. I wish i could give you a noble prize but for now thank you so much!!!!!!!!

Answer 52

lol you are welcome :)))))