Question

2x^3e^−3x − 5x^4e^−3x = 0 Ah help! I gotta solve for x, and there should be two answers for it right?

Answer 1

hint
\[e^{-3x}\] is never zero
so completely ignore that part

Answer 2

i.e. solve
\[2x^3-5x^4=0\] which cannot be too hard

Answer 3

oh that makes sense! so i would turn it into x^3(2-5x)=0 right?

Answer 4

yes

Answer 5

so then i would get 2=5x, which is 5/2, and then 0

Answer 6

yes

Answer 7

you are awesome! thanks so much!

Answer 8

yw (blush)