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Mathematics 22 Online
OpenStudy (anonymous):

What is the amplitude, period, and phase shift of f(x) = −4 sin(2x + π) − 5?

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

i need help knowing which is which and how to interpret the data

OpenStudy (kropot72):

You need to use the general equation: \[y=A \sin (Bx+C)+D\] where |A| = amplitude Period T = (2 pi)/B Phase shift = C/B

OpenStudy (anonymous):

ok then the amplitude would be -4 the period (2 pi)/2 phase pi/2

OpenStudy (kropot72):

Can you take a careful look at the amplitude; Amplitude = |A|

OpenStudy (anonymous):

oh so its 4

OpenStudy (kropot72):

Correct. You can simplify your result for the period.

OpenStudy (anonymous):

ok thank you very much i understand really well now.

OpenStudy (kropot72):

You're welcome :)

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