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What is the amplitude, period, and phase shift of f(x) = −4 sin(2x + π) − 5?
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@satellite73
@jim_thompson5910
i need help knowing which is which and how to interpret the data
You need to use the general equation: \[y=A \sin (Bx+C)+D\] where |A| = amplitude Period T = (2 pi)/B Phase shift = C/B
ok then the amplitude would be -4 the period (2 pi)/2 phase pi/2
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Can you take a careful look at the amplitude; Amplitude = |A|
oh so its 4
Correct. You can simplify your result for the period.
ok thank you very much i understand really well now.
You're welcome :)
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