Question

HELP HELP HELP HELP HELPLPLPLPL?!?!?!?!!?!?1



What exponential function represents the data in the table?


x f(x)
2 25
3 125
4 625
f(x) = x4 + 9

f(x) = 4x + 9

f(x) = x5

f(x) = 5x

Answer 1

Do you at least see the pattern that is going on in the table?

Answer 2

increasing by 25?

Answer 3

well what happens when going from f(2) to f(3), and what happens from f(3) to f(4)

Answer 4

you add 500 ?

Answer 5

ok that is true for f(3) to f(4), but it isn't true for f(2) to f(3). You want a rule that will be "the same" for both increases from f(2) to f(3), and from f(3) to f(4)

Answer 6

you can get help from the choices they listed

Answer 7

(since the increase from f(2) to f(3), and from f(3) to f(4) is not constant (i.e. it is not the same amount that you add to go from f(2) to f(3), and for f(3) to f(4) ), you should be thinking about at least ding some kind of multiplication (since this will increase your numbers quickly)

Answer 8

25 --?--> 125

125 --?--> 625

Answer 9

*5 both

Answer 10

perfect :)
That should narrow it down to c) and d) , since there some kind of *5 going on there.

WHat you can do is substitute the number of x into the rule and see if you get f(x)

for c)
\(2^5=25?\) (for x = 2)
\(3^5=125?\) (for x = 3)
\(4^5=625?\) (for x = 4)

for d)
\(5^2=25?\) (for x = 2)
\(5^3=125?\) (for x = 3)
\(5^4=625?\) (for x = 4)

Answer 11

wait so its d ?

Answer 12

yes absolutely. How it relates to what I was doing with the *5:
25 = 5*5 = \(5^2\)

Now 25 * 5 = 125
= (5*5) * 5 = 125 = \(5^3\)

And
125 * 5 = 625
=(5*5*5)*5 = 625 = \(5^4\)