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Mathematics 19 Online
OpenStudy (help!!!!):

Help me factor this

OpenStudy (imstuck):

Whatcha got?

OpenStudy (help!!!!):

250x^4 + 128x

OpenStudy (imstuck):

Well, you know the first thing you can do is take out an x.

OpenStudy (help!!!!):

Oh wow I didn't think of that. Then you use the special formula for cubic binomial right?

OpenStudy (imstuck):

Then you work on the numbers. They are both even so you know you can start by factoring out at least a 2. When you factor out an x and a 2, you are left with:\[2x(125x ^{3}+64)\]

OpenStudy (imstuck):

Then yes you use the formula to factor the sum of perfect cubes. Good!

OpenStudy (help!!!!):

After you simplify the 2 sums by 3

OpenStudy (help!!!!):

Is 216+343a^3 the farthest I can divide any sum?

OpenStudy (imstuck):

You need to find the cube root of 125 and that will be your "a"; you need to find the cubed root of 64 and that will be your "b". then you fit those into this formula:\[a ^{3}+b ^{3}=(a+b)(a ^{2}-ab+b ^{2})\]

OpenStudy (help!!!!):

And the answer would be (4x+1) 16x^2-42a+36 right?

OpenStudy (imstuck):

Im doing it now...hold on a sec.

OpenStudy (imstuck):

The result would be this:

OpenStudy (help!!!!):

Yup I got it, thank you so much

OpenStudy (imstuck):

\[2x(5x+4)(25x ^{2}-20x+16)\]

OpenStudy (imstuck):

and that doesn't factor any further without running into imaginary numbers as solutions. So you're good to go! TY for the medal! You upped my SmartScore to 71!

OpenStudy (help!!!!):

Ty for clarifying 2x :)

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