Help me factor this
Whatcha got?
250x^4 + 128x
Well, you know the first thing you can do is take out an x.
Oh wow I didn't think of that. Then you use the special formula for cubic binomial right?
Then you work on the numbers. They are both even so you know you can start by factoring out at least a 2. When you factor out an x and a 2, you are left with:\[2x(125x ^{3}+64)\]
Then yes you use the formula to factor the sum of perfect cubes. Good!
After you simplify the 2 sums by 3
Is 216+343a^3 the farthest I can divide any sum?
You need to find the cube root of 125 and that will be your "a"; you need to find the cubed root of 64 and that will be your "b". then you fit those into this formula:\[a ^{3}+b ^{3}=(a+b)(a ^{2}-ab+b ^{2})\]
And the answer would be (4x+1) 16x^2-42a+36 right?
Im doing it now...hold on a sec.
The result would be this:
Yup I got it, thank you so much
\[2x(5x+4)(25x ^{2}-20x+16)\]
and that doesn't factor any further without running into imaginary numbers as solutions. So you're good to go! TY for the medal! You upped my SmartScore to 71!
Ty for clarifying 2x :)
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