Which of the following processes has an increase in entropy?
A) Boiling a pot of water B) Freezing a sample of water C) Filtering sand out of a sample of water D) Synthesizing water from hydrogen and oxygen
I think it is B
not quite, think about what entropy is normally defined as "randomness". Freezing water fixes the location of atoms/molecules, so you're actually decreasing the "randomness" of the system.
So will it be D?
hm no. by taking 2 molecules (\(O_2\) and \(H_2\)) and making them one (water), you're actually decreasing the entropy of the system. You want a scenario where the spacing between molecules (and their ability to move) is greater than what you started with. Or making 2 (or more) things out of 1, e.g. decomposition reactions.
So it will be a because when you boil water the molecules space out and become gas
@aaronq Am i correct? I'm not 100% sure
yep! thats exactly it
Can you help me with another question?
shoot
Which of the following changes has a decrease in entropy? A) N2O4 ---> 2NO2 B) C6G6----> C6H6 C) 2LiCIO3 ---> 3O2+2LiCl D)3Fe=2O2---> fe3O4 Would it be c because they are two elements coming out of it?
it's not C. Recall that making more particles (from those that you started with) is an \(\sf increase\) in randomness.
So its D?
\(\Large \checkmark\)
I have two more that i need help on. one i don't even know what to put
post them?
Which of the following changes will always be true for a system with increasing entropy? A) - (triangle) G B) +(triangle)T C) +(triangle)S D) -(triangle)H
S means entropy
\(\Delta \) means change
so its c
yep
Which of the following combinations will result in a reaction that is never spontaneous? A) Positive enthalpy change and positive entropy change B) Positive enthalpy change and negative entropy change C) Negative enthalpy change and positive entropy change D)Negative enthalpy change and Negative entropy change
I think its C
That would actually be always spontaneous. This formula is the guideline for spontaneity of chemical reactions: \(\Delta G=\Delta H-T\Delta S\) \(\Delta G<0\) spontaneous \(\Delta G>0\) non-spontaneous
so it will be b
yes!
Thanks for the help!
no problem!
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