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Chemistry 19 Online
OpenStudy (anonymous):

Which of the following processes has an increase in entropy?

OpenStudy (anonymous):

A) Boiling a pot of water B) Freezing a sample of water C) Filtering sand out of a sample of water D) Synthesizing water from hydrogen and oxygen

OpenStudy (anonymous):

I think it is B

OpenStudy (aaronq):

not quite, think about what entropy is normally defined as "randomness". Freezing water fixes the location of atoms/molecules, so you're actually decreasing the "randomness" of the system.

OpenStudy (anonymous):

So will it be D?

OpenStudy (aaronq):

hm no. by taking 2 molecules (\(O_2\) and \(H_2\)) and making them one (water), you're actually decreasing the entropy of the system. You want a scenario where the spacing between molecules (and their ability to move) is greater than what you started with. Or making 2 (or more) things out of 1, e.g. decomposition reactions.

OpenStudy (anonymous):

So it will be a because when you boil water the molecules space out and become gas

OpenStudy (anonymous):

@aaronq Am i correct? I'm not 100% sure

OpenStudy (aaronq):

yep! thats exactly it

OpenStudy (anonymous):

Can you help me with another question?

OpenStudy (aaronq):

shoot

OpenStudy (anonymous):

Which of the following changes has a decrease in entropy? A) N2O4 ---> 2NO2 B) C6G6----> C6H6 C) 2LiCIO3 ---> 3O2+2LiCl D)3Fe=2O2---> fe3O4 Would it be c because they are two elements coming out of it?

OpenStudy (aaronq):

it's not C. Recall that making more particles (from those that you started with) is an \(\sf increase\) in randomness.

OpenStudy (anonymous):

So its D?

OpenStudy (aaronq):

\(\Large \checkmark\)

OpenStudy (anonymous):

I have two more that i need help on. one i don't even know what to put

OpenStudy (aaronq):

post them?

OpenStudy (anonymous):

Which of the following changes will always be true for a system with increasing entropy? A) - (triangle) G B) +(triangle)T C) +(triangle)S D) -(triangle)H

OpenStudy (aaronq):

S means entropy

OpenStudy (aaronq):

\(\Delta \) means change

OpenStudy (anonymous):

so its c

OpenStudy (aaronq):

yep

OpenStudy (anonymous):

Which of the following combinations will result in a reaction that is never spontaneous? A) Positive enthalpy change and positive entropy change B) Positive enthalpy change and negative entropy change C) Negative enthalpy change and positive entropy change D)Negative enthalpy change and Negative entropy change

OpenStudy (anonymous):

I think its C

OpenStudy (aaronq):

That would actually be always spontaneous. This formula is the guideline for spontaneity of chemical reactions: \(\Delta G=\Delta H-T\Delta S\) \(\Delta G<0\) spontaneous \(\Delta G>0\) non-spontaneous

OpenStudy (anonymous):

so it will be b

OpenStudy (aaronq):

yes!

OpenStudy (anonymous):

Thanks for the help!

OpenStudy (aaronq):

no problem!

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