Question

What is the solution of log(2x − 6) 256 = 4?

Answer 1

@mathmale

Answer 2

Divide both sides by 256
\[\log(2x-6)=4/256\]
\[a=\log _{b}(b^a)\]
\[\log _{10}(2x-6)=\log _{10(10^4/256}\]
They share the same base
\[2x-6=10^1/64\]

Answer 3

This is the question, sorry I might have wrote it wrong @Abmon98

Answer 4

@Hero

Answer 5

\[\log_{2x-6} 256=4\] \[\log_{2x-6} 256=\log_{2x-6} (2x-6)^4\]\[256=(2x-6)^4\] \[(256)^1/4=2x-6\] \[4=2x-6\]\[2x=10\]\[x=5\]

Answer 6

Wow, thank you so much :D

Answer 7

your welcome :D