HELP PLEASE? <3 You inherit $25000 and deposit it into an account that earns 4.5% annual interest compounded quarterly. How much money will be in the account after ten years?
Use the formula \[\Large A = P\left(1+\frac{r}{n}\right)^{n*t}\]
In this case, P = 25000 r = 0.045 (the decimal form of 4.5%) n = 4 (compounding quarterly) t = 10
I got 25000 (1+(0.045/4)^4(10)
now evaluate
When I calculate it comes out to 261441.2716. I'm not sure that seems right.
that's way too big
10 is in the exponent
so it should be 25000*(1+0.045/4)^(4*10)
evaluate that
Okay, so I put it in wrong. So, it is 39109.42163, right?
Very good, \[\Large A = P\left(1+\frac{r}{n}\right)^{n*t}\] \[\Large A = 25000\left(1+\frac{0.045}{4}\right)^{4*10}\] \[\Large A \approx 39,109.4216347769\] \[\Large A \approx 39,109.42\]
So you'll have $39,109.42 in the account in 10 years
Lovely~! Thank you. Would you mind if I ask you for help on one more part of the question set?
Earning 39,109.42 - 25,000 = 14,109.42 in interest
sure go ahead
If the interest were to be compounded continuously at 4.5%, how much money would be in the account after 10 years? And how many years you would reach your goal of 65,000, if the interest is compounded continuously. I got 21.4 years for how long it takes to get 65000.
And thank you for helping me with all of this. <3
So you were able to answer the second part of this? but not the first part?
I did it on my calculator quickly after you helped me just now.
how did you do it on your calculator?
When you showed me how to put in the formula, I changed the year, putting in 20. Since 10 gives you around 39 grand, So I looked to see if 20 would double it, but when it didn't I looked to se how much more I would have to put in and came up with around 21.
Am I not supposed to do it like that? o.o
well notice how it says "compounded continuously" so the formula is going to be (slightly) different
May I ask how so?
You will now use this formula \[\Large A = Pe^{rt}\] P is the amount you deposit or invest r is the interest rate (in decimal form) t is the time in years 'e' is a special constant (like pi) e = 2.71828182846...
The explanation as to why you use this formula for compounding continuously is a bit lengthy and it involves some advanced theory Here is the explanation http://www-stat.wharton.upenn.edu/~waterman/Teaching/IntroMath99/Class04/Notes/node13.htm Unfortunately it requires some background in calculus to fully understand how they're deriving the formula
anyways, you're taking the interest you've earned ($14,109.42) and you are depositing it into another account which continuously compounds interest for 10 years So P = 14,109.42 r = 0.045 t = 10 and you plug all that into \[\Large A = Pe^{rt}\]
So, 14,109.42e^(0.045*10)?
Doing it like that I get 39765.7485.
what did you type in to get that? that's too high
14,109.42x^(0.045*10). I can't find e on the calculator.
Would the x change it that much?
what kind of calculator do you have?
A graphing calculator. I could use the alpha, but I'm not sure how much of a difference that would make to change it to a e.
a texas instruments calculator?
Changing it to a e in the equation made it 0. And yes. A TI-84 Plus.
see the "LN" button (under the "Log" button)?
Yes.
above the LN is "e^x" so you hit the "2nd" key, then hit LN to get to e^x
Okay~! So, it would be 22127.97532.
good, that rounds to $22,127.98
Ahhh...~! Okay! Thank you so much! ^^
For the second part, the answer you got (21.4 years) is incorrect
Is it?
Yes, you need to solve for t in... A = P*e^(r*t) 65000 = 14109.42*e^(0.045*t)
I got 0. o.o
hmm odd
how are you getting 0?
Not sure. I'm putting it in the way you wrote it down. Could it be the letter?
I'll show you how I solved for t. A = P*e^(r*t) 65000 = 14109.42*e^(0.045*t) 65000/14109.42 = e^(0.045*t) 4.60685 = e^(0.045*t) ln(4.60685) = ln(e^(0.045*t)) ln(4.60685) = 0.045*t*ln(e) ln(4.60685) = 0.045*t*1 ln(4.60685) = 0.045*t ln(4.60685)/0.045 = t t = ln(4.60685)/0.045 t = 33.945429
the "ln" is really "LN" just with lowercase letters
So it takes roughly 33.945429 years to go from $14,109.42 to $65,000
That is so much. How do you retain it all? ;w;
tons and tons of practice
Oh, goodness. ><
The first step after you plug everything in is to isolate e^(0.045*t)
once you do that, you need to isolate t
and you use natural logs (LN) to do so
You explain this better than my teacher. o3o
Thanks. I'm glad it's clicking now.
Also, you'll use these log rules http://www.purplemath.com/modules/logrules.htm in this specific case, I used rule # 3
Okay. Thank you. :)
you're welcome
Can I ask you a general question? ><;
Just one more.
Go ahead
I am working on the next question right now and it asked me to identify the annual growth rate and the growth factor. What is the difference?
What's the full problem you're working on?
you deposit $2000 in an account that earns 5% annual interest compounded monthly.
There are two parts before that and I am on the last part.
how long are you depositing it for?
The first question was; What will your balance be after 2 years? The second question; Estimate how long it would take for your investment to double. I'm not sure if that tells you. It only says annually in the third question; Identify the annual growth rate and the growth factor.
it seems like this is a trick question because I think the annual growth rate is simply 5%
How would you come across that if you don't mind me asking?
it's given to you the 5% APR
OH! Okay. I read over that. ^^;;
as for the annual growth factor, that would be 1 + r/n = 1 + 0.05/12 = 1.0041667 which is approximate
Okay~! That makes more sense. Thank you. <3
you're welcome
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