Ask your own question, for FREE!
Chemistry 18 Online
OpenStudy (superhelp101):

Upon balancing the equation below, how many moles of calcium chloride are needed to react completely with 6.2 moles of silver nitrate? AgNO3 + CaCl2 yields AgCl + Ca(NO3)2 3.1 moles 6.2 moles 9.3 moles 12.4 moles

OpenStudy (superhelp101):

@asib1214

OpenStudy (somy):

balance the reaction

OpenStudy (somy):

then use this \[\frac{ mole~of~AgNO_3 }{ coefficient~ of~AgNO_3 } =\frac{ mole~of~CaCl_2 }{ coefficient~of~CaCl_2 }\]

OpenStudy (somy):

you know mole of AgNO3 and you will know coefficient when you balance the reaction mole of CaCl2 = X and coefficient again you will see it when u balance the equation

OpenStudy (superhelp101):

6.2 moles

OpenStudy (superhelp101):

??

OpenStudy (superhelp101):

@Somy

OpenStudy (somy):

did u balance the equation?

OpenStudy (somy):

please balance it and show it to me

OpenStudy (superhelp101):

mole of CaCl2 = X 111=X is this what you mean?

OpenStudy (somy):

NO

OpenStudy (somy):

Please write the balanced equation first i'll show the rest in another way

OpenStudy (superhelp101):

mole of AgNO3coefficient of AgNO3=mole of CaCl2coefficient of CaCl

OpenStudy (somy):

im sorry i meant reaction <.<

OpenStudy (somy):

AgNO3 + CaCl2 yields AgCl + Ca(NO3)2 this balance it

OpenStudy (superhelp101):

169.87+110.98 yields 143.32+164.088

OpenStudy (somy):

no.... i did not ask for molecular mass

OpenStudy (somy):

you dont know how to balance reactions?

OpenStudy (superhelp101):

i guess not :l

OpenStudy (somy):

i see well look AgNO3 + CaCl2------> AgCl + Ca(NO3)2 look at each atom on left of the arrow and right of the arrow

OpenStudy (somy):

you have to make it so that number of particular atom on the right is equal to the left

OpenStudy (somy):

lets take NO3 on left side there is only 1 NO3 on right side there are 2 NO3 do u see it?

OpenStudy (superhelp101):

no i dont can you please set it up so i can see it

OpenStudy (somy):

Ca(NO3)2 (NO3)2 2- means there are 2 of NO3

OpenStudy (somy):

i think you better watch this http://www.youtube.com/watch?v=RnGu3xO2h74 and learn only then we can proceed

OpenStudy (superhelp101):

ok

OpenStudy (somy):

@Abmon98 i need to leave now, can you explain him/her how to do it? explain about ratio and coefficients better and try doing it in steps, ok? @superhelp101 he will help you, if you don't get something - just ask him :) he is really good in chem :D

OpenStudy (superhelp101):

thank you!

OpenStudy (somy):

make sure to watch the video i gave you, if something not clear ask him ok? because before going any further you need to know how to balance chemical reactions

OpenStudy (superhelp101):

alright

OpenStudy (abmon98):

@Somy Thank you for choosing me :) and sure i ill AgNO3 + CaCl2 yields AgCl + Ca(NO3)2 Write down the number of atoms that you have on each side of the equation. On the Reactant Side: Ag:1 N:1 O:3 Ca:1 Cl:2 On the product side: Ag:1 N:2 O:6 Cl:2 Add a coefficient of 2 to AgCl AgNO3 + CaCl2 yields 2AgCl + Ca(NO3)2 On the Reactant Side:Ag:1 N:1 O:3 Ca:1 Cl:2 On the product side: Ag:2 N:2 O:6 Cl:2 now add a coeffcient of 2 to AgNO3 2AgNO3 + CaCl2 yields 2AgCl + Ca(NO3)2 On the Reactant Side:Ag:2 N:2 O:6 Ca:1 Cl:2 On the product side: Ag:2 N:2 O:6 Ca:1 Cl:2 A mole ratio is ratio between the amounts in moles of any two compounds involved in a chemical reaction. Ratio of mole of AgNO3 to CaCl2 2:1 6.2:x moles of CaCl2 Cross multiplication happens here 6.2*1/2=3.1 moles of CaCl2 are required to react completely with 6.2 moles of AgNO3

OpenStudy (superhelp101):

omg for you help @Abmon98 and @Somy after watching the video and your explanation it works out prefectly!

OpenStudy (abmon98):

Good to hear that :D

OpenStudy (somy):

thats good :))

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!