Integration help~
\[\Large \int \frac{x~dx}{3+\sqrt{x}}\]
i'm thinking multiply by the conjugate, did you try that?
Yup, got me to: \[\Large \int~\frac{x(3-\sqrt{x})}{9-x}~dx\] \[\Large \int~\frac{3x-x^{3/2}}{9-x}~dx\]
Not sure where to go now..
i was thinking we could split it up and use partial fractions, but i am doubting that now...
I tried a u-sub, but then that 3/2 power would be a problem, unless I'm overthinking it.
WolframAlpha says to do Substitution twice. First with u=root x, then do long division, the do substitution again with u=1/(u+3) Those steps should help.
To me, I let u =3+x^(1/2) --> du = 1/2x^(1/2) dx and x ^(1/2)=u-3 --> x = (u-3)^2 and from dx =2\(\sqrt x\)du replace x^1/2 = u -3 you have the outlet there
wolf usually doesn't have the best ways of doing things, though i'm sure that works
Yes use substitution 3 + sqrt(x) = u
yeah that works
Cool, good to know ^_^
Oh, alright, thanks guys :)
U r welcome :)
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