Question

Determine the number of solutions the system of 1/2y-5=2 and y=3(2x+5) will have
A)no solutions
B)impossible to determine
C)one solution
D)infinite solutions

Answer 1

is that \(\frac{1}{2}y\) or \(\frac{1}{2y}\)?

Answer 2

the first one

Answer 3

so you have one equation with a \(\color{blue}{y}\) in it on the left \(\frac{1}{2}\color{blue}{y}-5=2\). Then on the right you have another equation, where \(\color{blue}{y=3(2x+5)}\). So we can take that second equation and plug it into the first one.

\(\frac{1}{2}\color{blue}{y}-5=2\) becomes \(\frac{1}{2}3\color{blue}{(2x+5})-5=2\)

Answer 4

does this make sense?

Answer 5

so is it a. b. c or d?

Answer 6

can you solve that for x?

Answer 7

we are not here to give answers:(

Answer 8

It doesn't make sense if your trying to solve for x

Answer 9

why not?

Answer 10

srry don't get it

Answer 11

\(\frac{1}{2}3(2x+5)-5=2\) distribute the 1/2
\(\\3x+\frac{5}{2}-5=2\) add 5 to both sides
\(\\3x+\frac{5}{2}=7\)
can you do it from ehre?

Answer 12

thank you I get it now