Question

A sample of a gas occupies 0.785L when the pressure is 243.4KPa and the temperature is 15C. Calculate the volume the gas will occupy at SATP.

Answer 1

the formula i'm using is P1V1/T1 = P2V2/T2

Answer 2

but i'm confused with V2 P@ and T2..............................

Answer 3

@tester97

Answer 4

Oh i forgot this sorry honey

Answer 5

its alright, stay cute!!!!

Answer 6

Thanks :)

Answer 7

1litres-->0.001m^3
0.785litres-->x x=0.785*0.001=0.000785m^3
Use Ideal Gas Equation:
PV=nRT
R is a gas constant and is equivalent to 8.31
Temperature is changed from 15 degrees to kelvin by adding to 273
0.000785*243.3*10^3=n*8.31*(273+15)
n=0.079 moles
The standard temperature is 273 K (0° Celsius) and the standard pressure is 1 atm pressure. At STP, one mole of gas occupies 22.4 L of volume (molar volume).
22.4*number of moles=Volume
22.4*0.079=V

Answer 8

this is how i did it.

V1=0.785L
P1=234.1KPa
T1=15C
P2=100KPa
T2=25C

P1V1/T1=P2V2/T2

234.1KPa X 0.785L/15C = 100KPa X V2/25C

25 cancels out from the right side and shifts to the left side because i'm trying to isolate the V2

25X183.76/25 = 100 KPa X V2

now 100 KPa cancels out from the right side and shifts to the left side

306.26/100KPa = V2

3.062L = V2


Check if i'm right guys???????

Answer 9

i'm working with SATP and not STP

Answer 10

@Somy

Answer 11

gay-lusac and other stuff right?

Answer 12

if you are referring to the gas laws then yes

Answer 13

asib you are correct

Answer 14

aight thanks for the feedback!!!!