The probability of drawing a blue marble from a bag is 2/5 . The probability of drawing a red marble from the bag is 1/5 . What is the probability of drawing a red marble or a blue marble from the bag?
A.2/5
B.4/5
C.2/25
D.3/5
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OpenStudy (anonymous):
Is it B?
OpenStudy (mathmate):
um...
OpenStudy (anonymous):
hmmm
OpenStudy (mathmate):
P(B)=2/5, P(R)=1/5
\(P(B\cap R)=P(B)+P(R)-P(B\cup R)\)
But since red and blue are independent, \(P(B\cup R)=0\)
so
\(P(B\cap R)=P(B)+P(R)= ? \)
OpenStudy (mathmate):
Erratum:
\(P(B\cup R)=P(B)+P(R)−P(B\cap R)\)
But since red and blue are independent, \(P(B\cap R)=0\)
so
\(P(B\cup R)=P(B)+P(R)=?\)
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OpenStudy (mathmate):
@VivaLaChloe1
Can you work out P(B)+P(R) and try again?
OpenStudy (anonymous):
So is it D? @satellite73
OpenStudy (anonymous):
@mathmate @tester97
OpenStudy (tester97):
I think its D :\
OpenStudy (anonymous):
Me too.
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OpenStudy (mathmate):
Correct, it's D.
OpenStudy (anonymous):
add !
OpenStudy (anonymous):
@mathmate a slight typo when you wrote \[P(B\cup R)=0\]
OpenStudy (anonymous):
I AM AN IDIOT.I MEANT D NOT B
OpenStudy (anonymous):
Ugh i'm so blind
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OpenStudy (mathmate):
@satellite73
Yes, it wasn't even a "slight" typo. lol Thank you for pointing it out.
I got the cups and caps inverted.
I put up an erratum below. Perhaps next time I just have to delete the mistaken one and start anew! :)