A second ball is dropped from an elevator accelerating up with 1m/s2, 1 second after the first ball is dropped. how does relative velocity of two ball changes with time?
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whitemonsterbunny17 (whitemonsterbunny17):
Sorry, but I have not learned Physics yet.
Maybe @Abhisar can help. (:
OpenStudy (cp9454):
@LolWolf
OpenStudy (anonymous):
Increases linearly.
OpenStudy (cp9454):
relative velocity increases linearly?
OpenStudy (abhisar):
are u sure @LolWolf ?
Can u xplain it why ?
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OpenStudy (anonymous):
Wait, no, that's their distance. Clearly I'm not thinking today. Their relative velocity remains constant.
OpenStudy (abhisar):
\(\huge\checkmark\)
OpenStudy (abhisar):
U got that @cp9454 ?
OpenStudy (cp9454):
reason why relative velocity is constant.
OpenStudy (anonymous):
Reason (for the sake of completeness):
\[
v(t)=at+v_0
\]And:
\[
v'(t)=a(t+1)
\]Then their relative velocity
\[
v_r=v'(t)-v(t)=1a-v_0
\]
Note that \(v_0<0\).
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OpenStudy (abhisar):
Correct !
because at the moment the ball is dropped(separated from the lift) its accelaration becomes 9.8 or g
OpenStudy (abhisar):
This accelaration is same for both the balls.
OpenStudy (abhisar):
Now u can see by the relation @LolWolf provided that the relative velocity will remain constant !