G: A PARALLEL B <1=X+3Y <2=2X+30 <3=5Y+20 FIND M<1 WHAT I KNOW : 2X+30+5Y+20=180
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Where is angle 1?
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Ok. What you wrote above is correct. Angles 2 and 3 are same side interior angles, so they are supplementary. That means the sum of their measures is 180. That gives you one equation. What are angles 1 and 3 called?
CORRESPONDING THERE CONG
Can you please use small case letters?
Yes, that's correct. What do you know about corresponding angles of parallel lines?
Oh, I see, you already wrote cong. Ok, angles 1 and 3 are congruent. What equation do you get from that?
x+3y=5y+20
Great. Now you have two equations in two unknowns. You can solve the system of equations for x and y. Here is the system of equations: \(2x+30+5y+20=180\) \(x+3y=5y+20\) Do you know how to solve a system of equations?
does x=5y-17
No. You need to subtract 3y from both sides in the second equation, not 3.
2x + 30 + 5y + 20 = 180 x + 3y = 5y + 20 Let's combine like terms in the first equation: 2x + 5y + 50 = 180 Now let's subtract 50 from both sides: 2x + 5y = 130 Now, let's subtract 3y to the right in the second equation: x = 2y + 20
The two equations in our system now are: 2x + 5y = 130 x = 2y + 20 Since the second equation is solved for x, use the substitution method and substitute what x is equal to in the first equation. Then solve for x.
does m<1=70
Correct.
thanks
You're welcome.
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