Question

if the value of asintheta +bcostheta=c then the value of acostheta-bcostheta is

Answer 1

first square both the sides
then convert sintheta to costheta and solve

Answer 2

\[(a \sin \theta)^2+(b \cos \theta)^2=c^2\]

Answer 3

(asinx+bcosx)^2=c^2

Answer 4

no squaring is not done like that
you have to do the whole square

Answer 5

\[(asin \theta+bcos \theta)^{2}\]

Answer 6

a^2sin^2x+b^2cos^2x+2asinxbcox=c^2

Answer 7

for convenience i am using x

Answer 8

yup like that, and then change sintheta into costheta and solve

Answer 9

a-acos^2x+bcos^2x+2absinxcosx=c^2
a-cos^2x(a+b)+2absinxcosx=c^2

Answer 10

sorry in my question acostheta-bsinthetha to find

Answer 11

i am telling u wait.

Answer 12

i have solved in the attachment

Answer 13

i have many doubts

Answer 14

you have seen the attachment