Question

5x^2 +x-7=0 giving each solution correct to 2 decimal places

Answer 1

@tayromo

Answer 2

@abb0t

Answer 3

Use quadratic formula.

Answer 4

i want the answer not the way sorry

Answer 5

\[\frac{ -1\pm \sqrt{141} }{ 10 }\]

Answer 6

-1.28 and 1.08

Answer 7

and the working

Answer 8

@tayromo can u work it out

Answer 9

they are giving you the answers right above you. sorry i was working on something else

Answer 10

i want the working out @tayromo @cp9454

Answer 11

You have an equation in the quadratic form.

Answer 12

\[ax^2+bx+c=0\]
\[5x^2+x-7=0\]

Answer 13

So you can use the quadratic equation.

Answer 14

Quadratic equation:
\[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

Answer 15

Identify your a, b and c then plug and solve.

Answer 16

can u work it out pls @Johnbc

Answer 17

@yanee
@Squirrels

Answer 18

@AmericaS

Answer 19

can someone work it out and tell the answer plssssss

Answer 20

Um, math isn't my best subject. :( Sorry.

Answer 21

its ok

Answer 22

@cp9454 can u work it and explain

Answer 23

it has been worked out Hari. They gave you the equation and the answers. They are just in separate boxes

Answer 24

lol not the working out

Answer 25

All you have to do is plug the values in and solve.

Answer 26

work it out plssssssssss

Answer 27

which is a b c

Answer 28

They correspond to the coefficients of the quadratic form. So for your case compare the quadratic form with your quadratic and you will see that
a = 5
b = 1
c = -7

Answer 29

@hari5789 read the rules.

Answer 30

\[5x^2+x-7=0\]
quadratic formulea
\[x=-b \pm \sqrt{b^2-4ac} / 2a\]
a=5, b=1, c=-7
\[x=-1 \pm \sqrt{1^2-4(5)(-7)}/2(5)\]
\[x=-1 \pm \sqrt{141}/10\]
\[x=-1-\sqrt{141}/10=-1.29\]
\[x=-1+\sqrt{141}/10=1.09\]
so the answer is x=-1.29 and x=1.09