Question

If x=2

Solve for x:

x+8

@shrutipande9

Answer 1

10

Answer 2

o_O ten?

Answer 3

Oh wait, sorry. x+8=5

Answer 4

x= -3

Answer 5

How you do that.

Answer 6

x+8 = 5
x = 5-8
x = -3

Answer 7

This would work better if you used latex then explained your steps @cp9454

Answer 8

i didn't knew that, how to use that?

Answer 9

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Answer 10

thank u @tester97

Answer 11

I just don't how to do that. I've tried everything. I assumed x as ket vector <x| then found its eigenvalue by using a hermitian matrix to find lambda then applied Schrödinger's time-dependent variable to find the given state of the qubit:

\[i \hbar \frac{ \partial }{ \partial t }\psi (r,t) = [\frac{ -\hbar }{ 2m} gradient^2 +V(r,t)]\Psi (r,t)\]

Answer 12

welcome :)

Answer 13

Then I applied U-substitution to find the initial state of a qubit before it is observed in a plus/minus basis and then used Grover's algorithm to search through a lattice of N-Indexes.

Answer 14

I'm not following here...

Answer 15

Just hold on... let's take this back a few steps... How do I start this?

Answer 16

Jesus Christ... can anyone help me with this? I'm trying to finish my homework :(

Answer 17

first explain your question or write it properly.

Answer 18

If x=2

Solve for x:

x+8=5

Answer 19

look it is given that x=2, and from given equation we are getting x=-3
since, \[-3 \neq 2 \]
therefore \[x \in \phi\]. means no solution.

Answer 20

How you do that

Answer 21

Dont forget to medal people for all their hard work :)

Answer 22

I'm not following :( I gather that first you would find it's Eigenvalue by using a transposed hermitian matrix:

\[H(dis.)+|x>=\lambda + |x> \]

Correct?