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integral of dx/2x^2 +4x +3
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complete the square in the denominator and try a trig substitution
well... could it be like this... \[\int\limits_{}^{}\frac{ dx }{ 2x ^{2}+4x+3 }= \frac{ 1 }{ 2 }\int\limits_{}^{}\frac{ dx }{ (x+1)^{2}+1}\]
Excellent ! looks like u substitution will do : u = x+1
I am often amazed that how dumb I am. I was going to do a trig substitution lol.
so then,\[(\tan ^{-1} x+1) +c\]
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haha i was about to do the same lol
looks good^^ don't forget the 1/2 which you have factored out earlier
ah...haha i missed it
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