Question

<1 and <2 are complementary. If m<1 = 63^0 and m<2 = 12 + x, then find the value of x
Help Please! :)

Answer 1

hint : complementary angles add up to `90` degrees

Answer 2

so it would be like 63^0 +12 +x = 90? If so what do I do for the 0?

Answer 3

Yes !

\(\large 63^{\circ}\) - \(\large \circ \) is a symbol representing the unit ` degrees`

Answer 4

\(\large 63^{\circ} + 12+x = 90^{\circ}\)

Answer 5

solve \(x\)

Answer 6

you may ignore it when solving the equation - it exists just to tell you that the angle i sin degrees and not in some other crazy units...

Answer 7

solve it as if the equation is :

\(\large 63+ 12+x = 90\)

Answer 8

so 75x=90??

Answer 9

wait wait I take it back It would be like
x=15

Answer 10

x=15 is \(\large \color{red}{\checkmark}\)