Question

A chemist mixes 12 mol H2 with 5 mol N2. How much ammonia could be synthesized by this combination?

Answer 1

anybody?

Answer 2

N2+3H2-->2NH3
Look at the mole ratio of N2 to H2 based on the 12 moles of H2.
1:3
x:12 x=12*1/3=4 mole,
Now look at the mole ratio of N2 to H2 based on 5 mole of N2
1:3
5:x x=5*3/1=15 mole
The calculated value(15mole) is greater than present moles of hydrogen therefore hydrogen is the limting reagent
The limiting reagent is the reactant that is completely used up in a reaction and thus determines when the reaction stops, so we use the number of moles of hydrogen to calculate the number of moles of ammonia
mole ratio of H2 to NH3
3:2
12:x mole of ammonia
12*2/3=8mole of ammonia

Answer 3

thank you so much!

Answer 4

Your most welcome :)

Answer 5

yep it's the last one, i get about 8.22 moles bah yah!!!