Question

If 5.85 grams of cobalt metal react with 15.8 grams of silver nitrate, how many grams of silver metal can be formed and how many grams of the excess reactant will be left over when the reaction is complete? Show all of your work.

unbalanced equation: Co + AgNO3 “yields”/ Co(NO3)2 + Ag
I balanced it
Co + 2AgNO3 --> Co(NO3)2 + 2Ag

Answer 1

Step 1
find moles of each

Answer 2

you have masses given for you

Answer 3

mole= mass/ molar mass

Answer 4

Moles of Co and AgNO3?
I know the math by the way i just need to be sure

Answer 5

?

Answer 6

yes

Answer 7

do the calculation here and show what you are getting so that we confirm it :) and then move to next step :D

Answer 8

Ok...
Co = 5.85 g / 58.933 g/mol= 0.0993
AgNO3 = 15.8 g / 169.8717 g/mol= 0.0930? I think i did this one wrong

Answer 9

AgNO3 is the LR

Answer 10

Hello?

Answer 11

sorry yes im here
why you think you did that one wrong?

Answer 12

Never mind. i checked it aging

Answer 13

alright well i think you did it right

Answer 14

K what's next?

Answer 15

Which one is limiting now?

Answer 16

AgNO3

Answer 17

alright good
now Limiting reagent as you know finishes first

Answer 18

k

Answer 19

that is why reaction/amount of product depends on limiting reagent

Answer 20

Wait am i supposed to do something else now? sorry i just have not been doing this for a while and need a refresh

Answer 21

thats why we use mole of limiting reagent
and we look at the ratio
(meaning coefficients)

Answer 22

right

Answer 23

Number of Moles=Mass(g)/Molar Mass(g/mol)
Co + 2AgNO3-->Co(NO3)2 + 2 Ag
5.85/58.9=0.0993 moles of Cobalt
15.8/169.8=0.093 moles of Silver Nitrate
Look at the mole ratio of Co to AgNO3
1:2
0.0993:x
moles AgNO3 required = 0.0993 x 2 = 0.199
limiting reagent is the reactant that is completely used up in a reaction and thus determines when the reaction stops. The number of moles required(calculated) is greater than the present number of mole therefore AgNO3 moles is the limiting reagent.

How many grams of silver metal can be formed?
Ratio of moles of 2AgNO3 to Ag
2:2 they share the same number of moles
0.093*107.8=

How many grams of the excess reactant will be left over when the reaction is complete?
Look at the mole Ratio of Co to AgNO3
1:2
x :0.0930 x=0.0930*1/2=0.0465
0.0993-0.0465=Mass of left over reactant

Answer 24

Awesome job as always!!! @Abmon98
sorry my pc internet went off <.<

Answer 25

Thank you :D
No Problem