Question

what is the center of the following circle?
(x+12)^2+(y+6)^2=64

Answer 1

center is (-12,-6)

Answer 2

Help plz :C Thankew

Answer 3

The center of a circle is (h, k).
Your current equation is basically this: (x – h)^2 + (y – k)^2 = r2
So your center will be (-12, -6).

Answer 4

@UserA113 http://www.math-aids.com/images/pythagorean-definition-05.png <-- use the pythagorean theorem

Answer 5

\(\bf (x-{\color{blue}{ h}})^2+(y-{\color{brown}{ k}})^2=r^2\qquad center\ ({\color{blue}{ h}},{\color{brown}{ k}})\)

Answer 6

ikk i tried its just confusingg

Answer 7

\(\large \bf c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b\)

Answer 8

is that the formula

Answer 9

for the pythagorean theorem. yes

Answer 10

my question is dif tho its like 117 x+3 and x

Answer 11

the picture doesn't look like that

Answer 12

b=35.78=16 root 5

Which is C