Please help omg. :(

In the pendulum formula T=2pi(sqrtL/g) , we use g = 9.8 m/s2 for the acceleration due to gravity on Earth. But what about on Mars? If an astronaut on the surface of Mars swings a 1-meter long pendulum, and it has a period of 3.27 seconds, what is the acceleration due to gravity, g, on Mars?

Question

Please help omg. :(

In the pendulum formula T=2pi(sqrtL/g) , we use g = 9.8 m/s2 for the acceleration due to gravity on Earth. But what about on Mars? If an astronaut on the surface of Mars swings a 1-meter long pendulum, and it has a period of 3.27 seconds, what is the acceleration due to gravity, g, on Mars?

anonymous · Answer

I'll show my work in a second.

anonymous · Answer

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