Question

Can anyone show me how to solve this equation?

Answer 1

\[2\sqrt{x+1}+2=4\]

Answer 2

@dan815 can u help me plz?

Answer 3

move the 2 over to the other side and divide everything by first

Answer 4

?

Answer 5

\[2\sqrt{x+1}+2-2=4-2\]
\[2/2\sqrt{x+1}=2/2\]
\[\sqrt{x+1}=1\]

Answer 6

2/2 = 1 -_-

Answer 7

\[\sqrt{x+1}=1\]
\[\sqrt{x+1}=1\]
\[x+1=1\]
x=0

Answer 8

o so you divide both sides by 2?

Answer 9

oh the 2nd step didnt come out right i square both sides

Answer 10

yes

Answer 11

wait what about the 2nd step?

Answer 12

\[(\sqrt{x+1})^2=1^2\]
\[x+1=1\\x=0\]

Answer 13

to get rid of the sqrt we square both sides

Answer 14

u helped a lawt

Answer 15

sure ^^

Answer 16

how do you check?

Answer 17

you can check by seeing that when you plug x=0 back in the it satisfies the eqn

Answer 18

\[2\sqrt{x+1}+2=4\\ 2\sqrt{0+1}+2=4\\2*1+2=4\]

Answer 19

\[2\sqrt{0+1}+2=4\]
\[2/2\sqrt{0+1}=2/2\]
\[\sqrt{0+1}^2=1^2\]
\[1=1\]
True

Answer 20

lol yes if u wanna take it that far!

Answer 21

@dan815 one more question did i type this right? http://prntscr.com/41626z

Answer 22

the sqrt goes over the +1 too

Answer 23

but yes its fine otherwise

Answer 24

yes ik i couldnt put it over it on word -_-

Answer 25

and thx

Answer 26

Is this good too @dan815 its the same one just with the check thingy http://prntscr.com/4163ns

Answer 27

yep looks good cam

Answer 28

k thx :)

Answer 29

again

Answer 30

If Word doesn't let you extend the radical sign over 1, you can always group the terms using parenthesis. Instead of √x + 1, you can use parenthesis: √(x+1).

Answer 31

oh ok thanks aum