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Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x f(x)=x^2-3 g(x)=sq3+x
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Let's do the first one f(g(x)...do you know how to do composition of functions?
can we find the g(f(x)) first
that the one i don't understand
Is that\[\sqrt{3+x}\]
yes
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So in that it is g(f(x)...we take the g(x) above and where ever we see an x we substitute the value for f(x)...so what would we end up with?
would the answer be g(f(x))=sq root 3+(x^2-3)=sq x^2=x
You seem to understand it quiet well..good job. So how about the other equation.
would the other one be f(g(x))=(sq root 3+x)^2-3=(3+x)-3=x
Winner winner chicken dinner..great job!!!!
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thank you i just wanted to make sure i did it right
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