What is the equation in point-slope form of the line passing through (-2, 1) and (4, 13)?
y - 1 = -2(x - 4)
y - 1 = 2(x + 2)
y - 13 = -2(x + 2)
y - 13 = 2(x + 4)
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OpenStudy (anonymous):
DO YOU KNOW HOW TO FIND THE SLOPE?
OpenStudy (anonymous):
Sorry for the caps, I'm not that excited about rise-over-run
OpenStudy (anonymous):
y2-y1/x2-x1
OpenStudy (anonymous):
but i dont know how to find the answer with all the equations as answers :(
OpenStudy (anonymous):
Alright so first we need the slope, and once we do, we can get rid of some answers bc the slopes are different on some numbers compared to others
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OpenStudy (anonymous):
Alright find the slope for me first and tell me what you get
OpenStudy (anonymous):
the slope is 2
OpenStudy (anonymous):
@doulikepiecauseidont
OpenStudy (anonymous):
Ok, so we're left with B and D since the A and C have slopes of -2
OpenStudy (anonymous):
D?
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OpenStudy (anonymous):
Wait
OpenStudy (anonymous):
\[\Huge y-y_1=m(x-x_1)\]
where m=slope
(x1,y1) is a point
OpenStudy (anonymous):
If we try B we see that it works and if we try D we see that when we do the (x-x1) part we should get (x-4) but our answers gives us (x+4) if we had -4 as the point it would be (x-(-4)) which equals (x+4)
OpenStudy (anonymous):
oh so its B
OpenStudy (anonymous):
Correct
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