1+Cos2A/Cos2A = Tan2A/TanA Prove the Identity
Are you sure this typed correctly? \({{\cos^2A} \over {\cos^2A}} = 1\) That would make your statement: \( 2 = {{\tan^2A} \over {\tan A}} \) and I'm not sure that is true.
hi this is what they gave us
This is what we have Atthment
Okay. The identity you want to prove is \(\large \displaystyle {{1-\cos(2A)} \over {\cos(2A)}} = {{\tan(2A)} \over {\tan A}}\) That's a bit different and I am willing to believe it might be true.
Do you know any of the double angle identities? If not do you know any of the sum and difference identities?
Here is the sum and difference identities for cos (in compressed form): \(\large \displaystyle \cos (\alpha \pm \beta) = \cos\alpha\cos\beta \mp \sin\alpha\sin\beta \) So what can you conclude \( \large \cos (2A) \) equals?
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