G: AC PERP BIS OF BD
#1-3TRUE/FALSE
1. AB CONG AD
2.
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OpenStudy (daisy.xoxo619):
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OpenStudy (aum):
ANY point on the perpendicular bisector AC will be equidistant from B and D.
OpenStudy (daisy.xoxo619):
so #1-2 are true?
OpenStudy (aum):
1) is True.
If E is ON the perpendicular bisector AC, then angle EBD = angle EDB. But if E is NOT on AC then 2) is False.
OpenStudy (daisy.xoxo619):
ok and #3 would be false or no
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OpenStudy (aum):
3) False. The two angles mentioned are not adjacent to each other.
OpenStudy (daisy.xoxo619):
do you know how to do # 4
OpenStudy (aum):
In how many ways can 2 points be selected from the 4 points A,E.M and C?
OpenStudy (daisy.xoxo619):
3
OpenStudy (aum):
No. 2 points be selected from the 4 points in 4C2 ways. What is 4C2 = ?
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OpenStudy (aum):
4C2 = 4! / (2! * 2!) = 4*3 / 2 = 6 ways.
The four points are A, E, M and C. You can select any two points in the following way:
AE
AM
AC
EM
EC
MC
(for a total of 6 ways). Out of these 6 ways, how many are perpendicular bisectors?
OpenStudy (daisy.xoxo619):
2 ?
OpenStudy (aum):
AE (not a perpendicular bisector)
AM (yes)
AC (yes)
EM (no)
EC (no)
MC (yes)
3 out of 6 are perpendicular bisectors. Therefore, the probability is ?