An observer in a hot-air balloon sights a building that is 50 m from the balloon's launch point. The balloon has risen 165 m. What is the angle of depression from the balloon to the building? Round to the nearest degree.

Question

anonymous · Answer

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anonymous · Answer

@jim_thompson5910 @Abhisar @Luigi0210 Pleaze help i will give medal and fan

anonymous · Answer

@lilia222 @LarsEighner @kimarhett @hba @genson0 @sammiegurl3 guys please i need help

luigi0210 · Answer

You could use $tan\theta$

anonymous · Answer

yea im rly rusty in this subject so i dont know how to do that

luigi0210 · Answer

That'll give you the interior angle of the triangle and you could find the angle of depression by subtracting it from $90^○$

anonymous · Answer

but how  do you do that like what equation do you use

luigi0210 · Answer

$\Large tan\theta=\frac{opposite}{adjacent}$

anonymous · Answer

if any

luigi0210 · Answer

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luigi0210 · Answer

In terms of theta that is

luigi0210 · Answer

So that would pretty much be $\Large tan\theta=\frac{50}{165}$

anonymous · Answer

i just did the math it is 73 degrees..... thank you

luigi0210 · Answer

Yup :)

anonymous · Answer

thanks again:) @Luigi0210