Question

can someone help me to solve .?

Answer 1

Rewrite each function into the form \[f(x)=a(x-b)^{2}+k\]
1.\[f(x)=2x ^{2}+16x+33\]

Answer 2

Can you write \(2x^2 + 16x + 33 = 2(x^2 + 8x) + 33\) ?

Answer 3

\[f(x)=2x ^{2}+16x+33\]\[2(x ^{2}+16x+33)\]\[=2(x ^{2}+8x+\frac{ 64 }{ 4})+33-\frac{ 64 }{ 2}\]\[=2(x+\frac{ 8 }{ 2 })^{2}+\frac{ 33-64 }{ 2}\]\[=2(x+\frac{ 8 }{ 2})^{2}-\frac{ 31 }{ 2}\]
a=2 h=-8/2 k=-31/2
v=-8/2,-31/2
I don't know if my answer is correct.?

Answer 4

You have done it but there is a correction 33 - 64/4 =( 66-64 )/2 = 1 and put 8/2 = 4

Answer 5

huh? I don't get it..?

Answer 6

What is \( 33 - \frac{64}{2}\) ?

Answer 7

-31/2 ?

Answer 8

No. \(33-\frac{64}{2} = 33-32 = 1\)