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Chemistry 21 Online
OpenStudy (anonymous):

need help. predict the group to which the element belongs whose unpaired electron has the following set of quantum numbers; n=3, l=1, m=0, s= +1/2

OpenStudy (aaronq):

n=3, means it's on level 3 l=1, means it's on the p orbital, so 3p m=0, means it's in the middle p orbital, so \(\sf 3p_y\) s= +1/2 (means that it's the first electron there, we already knew this from the question) |dw:1405010236973:dw| This means it's electron configuration is \([Ne]3s^23p^2\) and the element is Si, group IV

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