In the figure below, ∠DEC ≅ DCE, ∠B ≅ ∠F, and segment DF is congruent to segment DB. Point C is the point of intersection between segment AG and segment BD, while point E is the point of intersection between segment AG and segment DF. The figure shows a polygon comprised of three triangles, ABC, DEC, and GFE. Prove ΔABC ≅ ΔGFE.
http://learn.flvs.net/webdav/assessment_images/educator_geometry/v15/module05/05_08_3b.jpg
can't go there
maybe new linnk?
@Vispla22
we can first prove that CAB and GF are congruent angles because of vertical angles
they also gve us the information that abc is equal to efg
do you mean CAB is congruent to GFE?
CB should also be equalt to ef fo the angles to be the same
no acb and gef
sorry i mistyped
ok . so far we have acb and gef are congruent because they are vertical angles
yeah and dc is equal to de and cb is equal to ef
how would we justify that?
well, the angles have to be the same and the only way it would do that is if the lengths are equal
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wouldn't work see?
ok so what do we have to do then?
oh wait... they give you the info that the two angles are the same so it would have to be an iscoceles triangle
that's why dc=de and cb=ef
getting the two angles of each triangle we can then prove that CAB is equal to EGF because of the triangle sum theorm
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