The table shows the result of rolling a number cube several times. To the nearest percent, what is the experimental probability of rolling a 3 or a 6? A. 12% B. 30% C. 33% D. 40%
First, you find the total number of rolls/tries. Which is adding all of the numbers in the outcome. Then you find the probability of each number, 3 and 6. Like last problem, the probability is the number of tries/rolls over the total number of tries/rolls.
Then you add both probabilities together to get the answer.
Total number of rolls/tries is 21. Then 31 is the number of times outcome occurs
Remember, the total number of rolls/tries is the outcome added together. So it'll be 5+4+7+5+4+5
I see the confusion. My mistake. I'm referring to the number of tries.
so 1+2+3+4+5 ?
No, 5+4+7+5+4+5. That's the total amount of tries/rolls. Which is 30.
With that, you find the probability of getting number 3 and the probability of getting number 6.
30%?
or does 30 have nothing to do with the final answer?
@Dscdago
30 is the total amount. To find the probability of something, it's the number of times the outcome occurred/total amount. So for number 3, it'll be 7/30. Can you find the probability of number 6?
5/30
Yes. Now add the probability of 3 and 6. (7/30)+(5/30)
12/30. so would it be 12%?
Since decimals can be converted to percent, you can divide 12 by 30. 12/30
12 divided by 30 is 26
Hehe. Actually, 12 divided by 30 is .4
Convert .4 to a percent. Do you know how?
omg, sorry. I'm an idiot. & no, I don't
It's fine. To convert a decimal to percent, you move the decimal point two places to the right. Remember that in .4, after the 4 there are 0's, but they are not written.
If you want to convert from percent to decimal, is the same process, but instead of moving the decimal point to the right, you move it to the left.
40%?
That's it!
thank you so much
I'm glad I could help.
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