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Mathematics 20 Online
OpenStudy (anonymous):

A. 85.33º B. 96.32º C. 79.39º D. 92.82º

OpenStudy (anonymous):

OpenStudy (anonymous):

you need the law of cosines for this one

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

i guess we need another picture

OpenStudy (anonymous):

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OpenStudy (cp9454):

How she will find length of a for applying law of cosines

OpenStudy (anonymous):

you are looking for angle \(B\)

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

first you need side \(a\) via \[a^2=b^2+c^2-bc\cos(45)\] or \[a^2=60.5^2+90^2-2\times 60.5\times 90\times \cos(45)\]

OpenStudy (anonymous):

once you get \(a\) you can use the law of sines to find angle \(B\)

OpenStudy (anonymous):

a= 4059.85 (??)

OpenStudy (anonymous):

hold on let me check

OpenStudy (anonymous):

that is \(a^2\) so \(a=63.7\) approx

OpenStudy (anonymous):

now \[\frac{\sin(B)}{90}=\frac{\sin(45)}{63.7}\]

OpenStudy (anonymous):

making \[\large B=\sin^{-1}\left(\frac{90\sin(45)}{63.7}\right)\]

OpenStudy (anonymous):

1?

OpenStudy (anonymous):

i guess that is the closest maybe some rounding error

OpenStudy (anonymous):

if you take the square root out to more digits i only kept one decimal place

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