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A. 85.33º B. 96.32º C. 79.39º D. 92.82º
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you need the law of cosines for this one
ok
i guess we need another picture
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How she will find length of a for applying law of cosines
you are looking for angle \(B\)
yes
first you need side \(a\) via \[a^2=b^2+c^2-bc\cos(45)\] or \[a^2=60.5^2+90^2-2\times 60.5\times 90\times \cos(45)\]
once you get \(a\) you can use the law of sines to find angle \(B\)
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a= 4059.85 (??)
hold on let me check
that is \(a^2\) so \(a=63.7\) approx
now \[\frac{\sin(B)}{90}=\frac{\sin(45)}{63.7}\]
making \[\large B=\sin^{-1}\left(\frac{90\sin(45)}{63.7}\right)\]
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1?
i guess that is the closest maybe some rounding error
if you take the square root out to more digits i only kept one decimal place
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