Can anyone help me!?!?!?!?! Here is my question:
Compare the functions shown below:
f(x) = 4 sin (2x − π) - 1
g(x)

x y
-1 6
0 1
1 -2
2 -3
3 -2
4 1
5 6
h(x) = (x − 2)2 + 4

Which function has the smallest minimum y-value?

Question

Can anyone help me!?!?!?!?! Here is my question:
Compare the functions shown below:
f(x) = 4 sin (2x − π) - 1	
g(x)

x	y
-1	6
0	1
1	-2
2	-3
3	-2
4	1
5	6
h(x) = (x − 2)2 + 4

Which function has the smallest minimum y-value?

anonymous · Answer

can you help me @nelsonjedi

anonymous · Answer

@satellite73

anonymous · Answer

the minimum value of $f(x) = 4 \sin (2x − π) - 1 $ is if sine is equal to $-1$ in which case you would get 
$$4\times (-1)-1=-5$$

anonymous · Answer

Smallest minimum value  What does that mean? I could read it either way?

anonymous · Answer

the minimum value of $g$ is apparently $-3$

anonymous · Answer

and the minimum value of $h(x) = (x − 2)^2 + 4 $ is $4$ since $(x-2)^2\geq 0$ always

anonymous · Answer

so whats the the lowest for f(x)

anonymous · Answer

-1?

anonymous · Answer

my best answer is above

anonymous · Answer

ok thankyou

anonymous · Answer

can you help me @kabrona

anonymous · Answer

i'll give you a medal and be your fan

anonymous · Answer

or nah

anonymous · Answer

anyways look up the song nae nae

anonymous · Answer

LoL @maemaehoowahh

anonymous · Answer

The correct answer was f(x), just took the test :)

anonymous · Answer

@malice you're a saint. thank you :D