A boy throws a ball up into the air with a speed of 8.2 m/s. The ball has a mass of 0.3 kg. How much gravitational potential energy will the ball have at the top of its flight? (Assume there is no air resistance.)

Question

festinger · Answer

Well, we first apply the conservation of energy. There are many variants of how it is presented, but I use this:

$$(KE_{top}-KE_{bottom})+(GPE_{top}-{GPE}_{bottom})=0$$
Where
$$GPE=mgh$$
and
$$KE=\frac{1}{2}mv^{2}$$

At the very top, what would the speed be? At the bottom what would the GPE be? If you have these 2, substituting them into the conservation of energy equation will give you the answer.

anonymous · Answer

Thank you so much, i got it correct ! :)