PLEASE HELP!!! find the equation of the line in slope-intercept form that is perpendicular to y=-1/2x+6 and passes through (3,-1)

Question

jim_thompson5910 · Answer

What's the slope of  y=-1/2x+6 ?

jim_thompson5910 · Answer

If you're not sure, remember the slope intercept form

y = mx+b

m is the slope

anonymous · Answer

The slope is -1/2

jim_thompson5910 · Answer

flip the fraction:  -1/2 -----> -2/1 = -2

Then flip the sign:  -2 -----> +2 = 2

jim_thompson5910 · Answer

The original slope is -1/2

The perpendicular slope is 2

jim_thompson5910 · Answer

So we want an equation that

A) has a slope of 2

B) goes through the point (3,-1)

jim_thompson5910 · Answer

do you know where to go from here?

anonymous · Answer

no I don't get it

jim_thompson5910 · Answer

do you see how I got the slope of 2?

anonymous · Answer

yes

jim_thompson5910 · Answer

now we use y = mx+b to find the equation

anonymous · Answer

so now it would be y=2x+b?

jim_thompson5910 · Answer

We have a slope m = 2
We have a point (x,y) = (3,-1)
Use them both to plug them into y = mx+b to find the equation


y = mx+b

y = 2x+b ... plug in the slope m = 2

-1 = 2*(3) + b ... plug in the point (x,y) = (3,-1)

b = ???

jim_thompson5910 · Answer

yes you're on the right track

anonymous · Answer

does B =-7?

jim_thompson5910 · Answer

very good

jim_thompson5910 · Answer

your equation is therefore

y = 2x - 7

anonymous · Answer

Thank you!!!

jim_thompson5910 · Answer

you're welcome