Help!!
Ok so this is it
ok so ths is the diffcult one for me
I cannot read the protractor in the first few...35-38 I can't see it.
Can you do those on your own?
can you give me an example?
Ok I fixed it
there i wrote them by hand to save you the troube
Thanks, that's perfect. In angle ADC, the only line you really have to worry about, per se, is the one with C at the end of it. That's the terminal end of the angle and the one that will give you the degree measure of the whole angle. The C crosses the protractor at 80 degrees, so the angle ADC is an 80 degree angle.
ADF is a straight line and straight lines ALWAYS measure 180 degrees.
oh wow am starting to get it
With angle FDB, the B line goes through the protractor at either the 25 degree mark or the 155 degree mark. Because this angle is opened up very widely, it is not a 25 degree angle. 25 degrees is tiny. So this angle is a 155 degree angle.
so you always go for the bigger one?
You only go for the bigger number if the angle is opened past the halfway mark which is 90 degrees. Like this:
would fde be 155 to?
|dw:1405056874652:dw||dw:1405056944885:dw|
Let me draw FDE for you...
oh so it would be 35
Oh yes! You're right! It's a small angle, smaller than the 90 degree half way point so it is acute.
yess!
You get it right? Angles that open up past 90 are obtuse and have the bigger number. Angles that open up less than 90 have the smaller number.
y
in #39, is EDC a straight line? I'm hoping it is...
i do now
not as straight as 40
so it is NOT a straight line. Perfectly straight...that's what i need to know.
its not perfectly straight once it passes d
Ok, then let me have a look at this one. 40 is easy. Let me study this one for a tiny...
ok!!
ooh, this one's a doozy.
hahahah
Let me try to explain it the best that i can. Look at the problem on your paper and follow along as i type, ok?
ok
Angles CDT and TDE add up to equal the meaure of the whole angle which is CDE, right?
Let me do that one again...
ok
Sorry...
no its fine
CDE = 44x-2 CDT = 34 Now here's the important part...
im grateful you helping me!!
TDE - CDT = TDE
You're welcome
Look at your picture. The whole angle is CDE which is 44x-2. The angle CDT is 34. When you take CDT away from CDE you're left with TDE. Do you see that?
The equation is this:
(44x-2) - 34 = 34x+4
That is exactly what we said when we used the angle letters. These are the values for those angles. Solving that for x you do this:
44x - 2 - 34= 34x + 4 44x - 36 = 34x + 4 44x-34x = 4 + 36 10x = 40 x = 4.
Now that we know x is 4, we can substitute 4 back in for x in the angle 34x+4, which is TDE, the one they are looking for.
34(4)+4=140
Angle TDE = 140
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