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How many grams of chlorine gas is required to completely react with 0.400g of hydrogen gas to yield hydrogen chloride gas
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H2+Cl2-->2HCL Number of Moles=Mass(g)/Molar Mass(g/mol) 0.400/1=0.400 moles Mole Ratio of H2 and Cl2 is 1:1 so they share the same number of moles Arrange the equation: Mass(g)=Molar Mass(g/mol)*Number of Moles 0.400*35.5=14.2
Also calculate the amount of HCl formed?
Why dont you try solving it
cause I don't know..pls
Look at the mole ratio from the balanced chemical equation of H2 Cl2 and HCL 1:1:2 0.4:0.4:0.8 Mass(g)=Molar Mass(g/mol)*Number of moles 0.8*(1+35.5)=Mass
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thanks :)
Your welcome :)
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