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Mathematics 16 Online
OpenStudy (anonymous):

Use the graph of y ≤ 4x2 + 12x + 10 to determine which of the following points is a solution. The domain and range of the window is from -10 to 10. http://prntscr.com/41qxfo A. (-2, 0) B. (-2, -1) C. (0, 0) D. (-1, 2)

OpenStudy (anonymous):

Plug in the x-coordinate and check to see if the corresponding y-coordinate is less than or equal to the right side of the inequality. For instance, take \((-2,0)\), then you have to check if the inequality holds: \[y\overbrace{\le}^{\large?}4x^2+12x+10~~\iff~~0\overbrace{\le}^{\large?}4(-2)^2+12(-2)+10\] The right side reduces to \(16-24+10=2\). Indeed, \(0\le2\), so \((-2,0)\) is a solution. The graph you provided is actually the one for \(y\color{red}{\ge}4x^2+12x+10\), so make sure you have the right inequality in mind.

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