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If f′ is continuous, f(7)=0, and f′(7)=11, evaluate
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\[\lim_{x \rightarrow 0} \frac{ f(7+3x)+f(7+5x)}{ x}\]
@dan815
ok
lhos[itsl since inderminate form
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l'hopital*
\[ \lim_{x \rightarrow 0} \frac{ f(7+3x)+f(7+5x)}{ x} = \lim_{x \rightarrow 0} \frac{ f(7+3x)}{x} +\lim_{x \rightarrow 0} \frac{(7+5x)}{ x} = \\ \lim_{x \rightarrow 0} 3\frac{ f(7+3x)}{3x} +\lim_{x \rightarrow 0} 7\frac{(7+5x)}{ 7x} \]
= 3f'(7) + 7f'(7)
|dw:1405119205032:dw|
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